SOLUTION: show that the area of any triangle given the length of sides a and b and included angle theta in between the two given sides is : {{{area = 1/2((ab)(sintheta)) }}}

Algebra ->  Geometry-proofs -> SOLUTION: show that the area of any triangle given the length of sides a and b and included angle theta in between the two given sides is : {{{area = 1/2((ab)(sintheta)) }}}      Log On


   

Question 283548: show that the area of any triangle given the length of sides a and b and included angle theta in between the two given sides is : area+=+1%2F2%28%28ab%29%28sintheta%29%29+
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I'm sure that's not right.
As a and b increase, the area decreases.
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It's %281%2F2%29%2Aa%2Ab%2Asin%28theta%29
b%2Asin%28theta%29 is the height of the triangle is a is called the base, and vice versa.
Area = bh/2