SOLUTION: I have been looking over mixture problems, and am quite comfortable solving 2 ingredient formulas, but I do not know the procedure if there are <b>MORE</b> than 2 ingredients.<br>

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: I have been looking over mixture problems, and am quite comfortable solving 2 ingredient formulas, but I do not know the procedure if there are <b>MORE</b> than 2 ingredients.<br>       Log On

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Question 283484: I have been looking over mixture problems, and am quite comfortable solving 2 ingredient formulas, but I do not know the procedure if there are MORE than 2 ingredients.

Example:

  • Candy A costs $2.00 lb & sells for $2.75
  • Candy B costs $3.25 lb & sells for $4.95
  • Candy C costs $2.25 lb & sells for $3.50
  • Candy D costs $1.00 lb & sells for $1.50

Create a mixture using all 4 candies that will sell for $3.95 while maximizing profits.

Found 2 solutions by richwmiller, Deina:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
How would you set this up for two ingredients?

Answer by Deina(147) About Me  (Show Source):
You can put this solution on YOUR website!
Set for just two ingredients

A larger output quantity will allow us to narrow in on the desired selling price easier, so we will do a total of 25 lbs.

Using only two ingredients, Candies B & D:

  • +4.95%28x%29+%2B+1.50%2825-x%29+=+3.95%2825%29+
  • +4.95x+%2B+37.5+-+1.5x+=+98.75+
  • +3.45x+%2B+37.5+=+98.75+
  • +3.45x+%2F+3.45+=+61.25+%2F+3.45+

x = 17.75 lbs of candy B
25 - 17.75 = 7.25 lbs of candy D