SOLUTION: 1. the product of two consecutive integers is 600.find the integers.(show working out) 2. the product of two consecutive even integers is 1848.find the integers.(show working out)

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Question 283295: 1. the product of two consecutive integers is 600.find the integers.(show working out)
2. the product of two consecutive even integers is 1848.find the integers.(show working out)
3.two positive integers differ by 12 and their product is 405.find the integers.(show working out)
topic is quadratic equations
Found 2 solutions by richwmiller, oberobic:
Answer by richwmiller(17219) (Show Source):
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Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website!
1. Two consecutive integers are best shown as: x and x+1.
(x)(x+1) = 600
x^2 + x -600 = 0
(x+25)(x-24) = 0
x=-25 or x=24
Answer:
The two consecutive integers are either 24 & 25 or -25 & -24.
...
2. Two consecutive even integers are best shown as: x and x+2.
(x)(x+2) = 1848
x^2+2x-1848 = 0
(x+44)(x-42) = 0
x = -44 or x=42
Answer:
The consecutive even integers are either -44 and -42 or 42 and 44.
...
3. Two positive integers differ by 12 is best shown as: x and x+12
(x)(x+12)=405
x^2 + 12x -405 = 0
(x+27)(x-15) = 0
x=-27 or x=15
BUT we are told positive numbers only,
x = 15 and x+12 = 27
...
Done