SOLUTION: I feel stupid asking this. I'm just starting to work on these?
The problem I got is
log2y=3
Now if I'm correct, I try to find x and convert this to
y=log(2)3
In which ca
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-> SOLUTION: I feel stupid asking this. I'm just starting to work on these?
The problem I got is
log2y=3
Now if I'm correct, I try to find x and convert this to
y=log(2)3
In which ca
Log On
Question 283089: I feel stupid asking this. I'm just starting to work on these?
The problem I got is
log2y=3
Now if I'm correct, I try to find x and convert this to
y=log(2)3
In which case, is it no solution?
Or am I completely off in how I'm working on these?
Thanks,
Nathalie Answer by nabla(475) (Show Source):
You can put this solution on YOUR website! Is that a log of base 2? By definition log_2(y)=3 means 2^3=y implies 8=y.
In words, the base of a log to the power of the other side of the equation is equal to what the log was of (this may be confusing and it certainly is not concise).
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