SOLUTION: how do you solve {{{((x^2+x-6)/(x^3)) * ((x)/(x^2-4))}}}

Algebra ->  Square-cubic-other-roots -> SOLUTION: how do you solve {{{((x^2+x-6)/(x^3)) * ((x)/(x^2-4))}}}      Log On


   

Question 283065: how do you solve %28%28x%5E2%2Bx-6%29%2F%28x%5E3%29%29+%2A+%28%28x%29%2F%28x%5E2-4%29%29
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
factor
x^2+x-6=(x+3)*(x-2)
x^2-4=(x+2)*(x-2)
(x-2) cancels out
x/x^2=1/x^2
so we get (x+3)/(x^2)*(x+2)