SOLUTION: Hello I not sure how to find these answers. 5x+x(x-2)=0 what are the solutions, also need to know what are the x-intercepts, thankyou would really appreciate your help.

Algebra ->  Radicals -> SOLUTION: Hello I not sure how to find these answers. 5x+x(x-2)=0 what are the solutions, also need to know what are the x-intercepts, thankyou would really appreciate your help.       Log On


   

Question 282917: Hello I not sure how to find these answers.
5x+x(x-2)=0 what are the solutions,
also need to know what are the x-intercepts,
thankyou would really appreciate your help.
Bette
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
5x%2Bx%28x-2%29=0 Start with the given equation.


5x%2Bx%5E2-2x=0 Distribute.


x%5E2%2B3x=0 Combine like terms.


x%28x%2B3%29=0 Factor out the GCF 'x'.



Now set each factor equal to zero:

x=0 or x%2B3=0


x=0 or x=-3 Now solve for x in each case


So the solutions are

x=0 or x=-3


Since the 'x' intercepts of y=5x%2Bx%28x-2%29 are simply the solutions of 5x%2Bx%28x-2%29=0, this means that the x-intercepts are (0,0) and (-3,0)