SOLUTION: How do I factor this completely: 128m^6 - 2n^6

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Question 282889: How do I factor this completely: 128m^6 - 2n^6
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
128m^6 - 2n^6

2(64m^6 - n^6)

2((4m^2)^3 - (n^2)^3)


2(4m^2 - n^2)((4m^2)^2+4m^2n^2+(n^2)^2)

2(4m^2 - n^2)(16m^4+4m^2n^2+n^4)


2(2m+n)(2m-n)(16m^4+4m^2n^2+n^4)


Answer: 128m^6 - 2n^6 = 2(2m+n)(2m-n)(16m^4+4m^2n^2+n^4)