SOLUTION: how do you solve this equation (4t-3)/5-(4-2t)/3=1 ? 3(4t-3)/15-5(4-2t)/15=1 12t-9-20+8t=15 20t-29=15 20t=44 t=44/20 t=11/5 t=2.2

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Question 282580: how do you solve this equation (4t-3)/5-(4-2t)/3=1 ?
3(4t-3)/15-5(4-2t)/15=1
12t-9-20+8t=15
20t-29=15
20t=44
t=44/20
t=11/5
t=2.2
Found 2 solutions by coolme4u, richwmiller:
Answer by coolme4u(1) About Me  (Show Source):
Answer by richwmiller(17219) About Me  (Show Source):
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t=2
how do you solve this equation (4t-3)/5-(4-2t)/3=1 ?
3(4t-3)/15-5(4-2t)/15=1
NOT 12t-9-20+8t=15 because -5*-2t=+10t
BUT 12t-9-20+10t=15
22t=44
t=2