SOLUTION: what are the steps to doing a pre algebra problem like 6(2b+7)3= I am learning about distributive property and Im in speacial education for my poor math skills

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: what are the steps to doing a pre algebra problem like 6(2b+7)3= I am learning about distributive property and Im in speacial education for my poor math skills      Log On


   

Question 282497: what are the steps to doing a pre algebra problem like 6(2b+7)3=
I am learning about distributive property and Im in speacial education for my poor math skills
Found 2 solutions by oberobic, Earlsdon:
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Show the multiplication to help keep yourself straight...
6(2b+7)3 = 6 * (2b + 7) * 3
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Since it doesn't matter what you multiply first, you can multiply what is outside the parentheses...
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6 * (2b + 7) * 3 = 6*3 * (2b+7) = 18 * (2b + 7)
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Now multiply that times what is inside the parentheses...
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18 * (2b+7) = 18*2b + 18*7
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Simplify..
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18*2b + 18*7 = 36b + 126
.
Done

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
6%282b%2B7%293 You can rewrite this as:
6%2A3%282b%2B7%29 Multiply the 6 by the 3 to get:
18%282b%2B7%29 In the distributive property, the number on the outside of the parentheses is to multiply both terms on the inside of the parentheses and this can be expressed as:
18%2A2b%2B18%2A7 Now perform the indicated multiplications.
highlight%2836b%2B126%29