SOLUTION: A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph. How long after the jogger started did the cyclist take over th
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Question 282321: A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph. How long after the jogger started did the cyclist take over the jogger? Round to the nearest tenth of an hour. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! A jogger started a course at 4.5 mph. A cyclist started the same course 1 hour later at an average speed of 14 mph. How long after the jogger started did the cyclist take over the jogger? Round to the nearest tenth of an hour.
let the cyclist meet the jogger at a distance x from the start
He starts after 1 hour after the jogger starts
so jogger would have traveled 4.5 miles by that time.
distance traveled by jogger when cyclist meets him will be x-4.5 miles
the time they travel after cyclist starts is the same.
time taken by jogger = x-4.5 / 4.5
time taken by cyclist = x/14
x/14 = x-4.5 /4.5
4.5x/14 = x-4.5
4.5x = 14(x-4.5)
4.5x= 14x- 63
-9.5x=-63
x= -63/-9.5
x=6.6 miles the distance they meet from the start
Time taken by jogger to jog (6.6-4.5) = 2.1 miles = 2.1/4.5= 0.46 hours
the cyclist meets the jogger after 1.46 hours after the jogger started
