SOLUTION: This trig. identity is also hard. Can you help me equal it? We are only allowed to work on one side of the problem. cos/sec + sin/csc = sec^2 - tan^2

Algebra ->  Trigonometry-basics -> SOLUTION: This trig. identity is also hard. Can you help me equal it? We are only allowed to work on one side of the problem. cos/sec + sin/csc = sec^2 - tan^2      Log On


   

Question 282268: This trig. identity is also hard. Can you help me equal it? We are only allowed to work on one side of the problem.
cos/sec + sin/csc = sec^2 - tan^2
Answer by xachu4u(10) About Me  (Show Source):
You can put this solution on YOUR website!
Is it not easy?
L.H.S is cos^2 + sin^2 , i.e =1
R.H.S is also 1 since
1 + tan^2 = sec^2