SOLUTION: how do you solve for (t) in this radical equation : (2t+1)^1/4 -1=2 ?

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Question 282226: how do you solve for (t) in this radical equation : (2t+1)^1/4 -1=2 ?
Found 3 solutions by Mathematicians, dabanfield, mananth:
Answer by Mathematicians(84) About Me  (Show Source):
You can put this solution on YOUR website!
%282t%2B1%29%5E1%2F4+-1=2 plus 1 on both sides
%282t%2B1%29%5E1%2F4+=+3 raise both sides to the fourth power
%282t%2B1%29+=+81 minus 1 on both sides
2t+=+80 divide both sides by 2
t+=+40

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
(2t+1)^1/4 -1=2 ?
(2t+1)^1/4 = 2 + 1
(2t+1)^1/4 = 3
Raise both sides to the 4th power:
((2t+1)^1/4)^4 = 3^4
(2t+1)^1 = 81
2t+1 = 81
2t = 80
t = 40

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(2t+1)^1/4 -1=2
(2t+1)^1/4 =2 +1
Take the 4th power on both sides of the equation
(2t+1)= 3^4
2t+ 3^4-1
2t=81-1
2t=80
t=40