SOLUTION: BETH WAS REQUIRED TO MAKE A CROSS-COUNTRY FLIGHT IN TRAINING FOR HER PILOT LICENSE . WHEN SHE FLEW FROM HER HOME AIRPORT A STEADY 30 MILES PER HOUR WIND WAS BEHIND HER AND THE TRIP
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-> SOLUTION: BETH WAS REQUIRED TO MAKE A CROSS-COUNTRY FLIGHT IN TRAINING FOR HER PILOT LICENSE . WHEN SHE FLEW FROM HER HOME AIRPORT A STEADY 30 MILES PER HOUR WIND WAS BEHIND HER AND THE TRIP
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Question 282205: BETH WAS REQUIRED TO MAKE A CROSS-COUNTRY FLIGHT IN TRAINING FOR HER PILOT LICENSE . WHEN SHE FLEW FROM HER HOME AIRPORT A STEADY 30 MILES PER HOUR WIND WAS BEHIND HER AND THE TRIP TOOK 5 HOURS. WHEN SHE RETURED AGAINST THE WIND THE FLIGHT TOOK 7 HOURS. FIND THE PLANES SPEED IN STILL AIR AND THE DISTANCE TRAVELED EACH WAY Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! BETH WAS REQUIRED TO MAKE A CROSS-COUNTRY FLIGHT IN TRAINING FOR HER PILOT LICENSE . WHEN SHE FLEW FROM HER HOME AIRPORT A STEADY 30 MILES PER HOUR WIND WAS BEHIND HER AND THE TRIP TOOK 5 HOURS. WHEN SHE RETURED AGAINST THE WIND THE FLIGHT TOOK 7 HOURS. FIND THE PLANES SPEED IN STILL AIR AND THE DISTANCE TRAVELED EACH WAY
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Assuming the wind was the same on the way back:
Her groundspeed going was a + 30 (a = airspeed)
Returning, it was a - 30
d = rt
d = (a+30)*5 = (a-30)*7
5a + 150 = 7a - 210
-2a = -360
a = 180 mph
d = 5*210 = 1050 miles
d = 7*150 = 1050 miles
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Beth would know that there is no "plane's speed in still air",
it's called airspeed.
