SOLUTION: The sides of a triangle measure 9, 15, and 18. If the shortest side of a similar triangle measures 6, find the length of the longest side of this triangle.

Algebra ->  Triangles -> SOLUTION: The sides of a triangle measure 9, 15, and 18. If the shortest side of a similar triangle measures 6, find the length of the longest side of this triangle.      Log On


   



Question 282054: The sides of a triangle measure 9, 15, and 18. If the shortest side of a similar triangle measures 6, find the length of the longest side of this triangle.
Found 2 solutions by Fombitz, arKed:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The first triangle has a ratio of sides as 9:15:18.
The similar triangle retains that ratio as 6:X:Y.
The multiplier is then,
9%2AA=6
A=6%2F9=2%2F3
So then
%282%2F3%29%289%3A15%3A18%29=6%3A10%3A12
The longest side would then be 12.

Answer by arKed(27) About Me  (Show Source):
You can put this solution on YOUR website!
Similar triangles
a1/a1 = b1=b2 = c1/c2
9/6 = 15/b2 = 18/c2
Since 18 is the longest side we will solve for c2
9/6 = 1.5
c2 = 18/1.5
longest side = 12