SOLUTION: find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers

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Question 281964: find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers
Answer by brucewill(101) About Me  (Show Source):
You can put this solution on YOUR website!
The three numbers would be x, x+2 and x+4.
3x is 3 times the first number
(x+2+x+4)-1 is one less than the sum of the second and third integers.
3x+=+x%2B2%2Bx%2B4-1
3x+=+2x+%2B+5
x+=+highlight+%285%29
Answer: 5, 7, 9.
Proof: 5*3 = 15
7+9-1 = 15