SOLUTION: The peroid T (in seconds) of a simple pendulum as a function of its length,L (in feet) is given by T(L)=2pi square root(L/32.2)
The question is to express the length,L as a fun
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-> SOLUTION: The peroid T (in seconds) of a simple pendulum as a function of its length,L (in feet) is given by T(L)=2pi square root(L/32.2)
The question is to express the length,L as a fun
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Question 281950: The peroid T (in seconds) of a simple pendulum as a function of its length,L (in feet) is given by T(L)=2pi square root(L/32.2)
The question is to express the length,L as a function of the period T. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! T(L)=2pi square root(L/32.2)
The question is to express the length,L as a function of the period T.
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T(L) = 2pi*sqrt(L/32.2)
sqrt(L/32.2) = T(L)/(2pi)
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Square both sides to get:
L/32.2 = [T(L)/(2pi)]^2
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L = 32.3[T/2pi]^2
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Cheers,
Stan H.
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