SOLUTION: A BOAT TRAVELING AT A SPEED OF 36 KM PER HOUR. IT HAS TO TRAVEL A DISTANCE OF 210 KM. HOW LONG WILL IT TAKE

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Question 281723: A BOAT TRAVELING AT A SPEED OF 36 KM PER HOUR. IT HAS TO TRAVEL A DISTANCE OF 210 KM. HOW LONG WILL IT TAKE
Found 2 solutions by Alan3354, PRMath:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You have 2 numbers to work with.
Give it a try.

Answer by PRMath(133) About Me  (Show Source):
You can put this solution on YOUR website!
A BOAT TRAVELING AT A SPEED OF 36 KM PER HOUR. IT HAS TO TRAVEL A DISTANCE OF 210 KM. HOW LONG WILL IT TAKE

You just need to know ONE equation about rate, time and distance.
You should always remember this equation:

Rate+%2A+Time+=+Distance

Let's put it in terms of variables:
Let's call Rate: R
Let's call Time: T
Let's call Distance: D


So now we have:
R+%2A+T+=+D or RT = D

What if you wanted to solve for R? Can you see that if you had RT = D that you could solve for "R" just by dividing T from both sides of the equation:

RT = D
R+=+D%2FT

What if you wanted to solve for T? Can you see that if you had RT = D, that you could solve for "T" just be dividing R from both sides of the equation:

RT = D
T+=+D%2FR

So now from just ONE equation: RT = D, you can "switch it around" so to speak and solve for Rate or you can solve for T.

In this problem, you want to solve for TIME. So, thinking of our one equation of RT = D, we realize we want to solve for T. Therefore, we should use this equation: T+=+D%2FR


What do we know?
We know the Rate is 36 km per hour. R = 36
We know the Distance is 210 miles. D = 210


Let's plug that info in:

T+=+D%2FR
T+=+210%2F36
T+=+5.83

SO the boat must travel for 5 hours and .83 of an hour. OR....
5 hours and
.83 of 60 minutes which is: 49.8 minutes (.83+%2A+60+=+49.8)


The boat must travel for 5 hours and 49.8 minutes.

I hope this helps you. :-)