SOLUTION: find three consecutive positive integers such that the product of the second and third integers is twenty more than ten times the first integer

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Question 281696: find three consecutive positive integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by Greenfinch(383) About Me  (Show Source):
You can put this solution on YOUR website!
If the numbers are X, X+1 and X+2
10X = (X+1)(X+2) - 20
10X = X^2 + 7X -18
X^2 -7X -18 =0
(X+2)(X-9) = 0
X = -2 or 9
since 2 is negative, the numbers are 9,10,11
CHECK 90 is 20 less than 110