SOLUTION: The perimeter of a triangle is 297 mm . If the lengths of the sides are consecutive odd intergers , find the lengths of the sides .

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Question 281584: The perimeter of a triangle is 297 mm . If the lengths of the sides are consecutive odd intergers , find the lengths of the sides .
Found 3 solutions by JBarnum, Alan3354, solver91311:
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
P=A+B+C
P=297
x=an odd number(Ex if x=5 then 5+2 is odd and 5+4 is odd making 5,7,9 consecutive odd numbers)
A=x
B=x+2
C=x+4
plug into the first equation
P=A%2BB%2BC
297=x%2Bx%2B2%2Bx%2B4
297=3x%2B6
291=3x
97=x
A=x=97
B=x+2=99
C=x+4=101

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
297/3 = 99, the middle number
--> 97, 99, 101

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I can't do this problem as stated because I don't know what an interger is. But if you want a solution involving consecutive integers, then I can help.

Let represent the first of the three consecutive odd integers. Then represents the next consecutive odd integer and represents the last of the three:

Since the perimeter of any figure is the sum of the measures of the sides:




Just solve for

John