SOLUTION: Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a co
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a co
Log On
Question 281439: Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a constant rate, the number of minutes before Jessica laps Sharon is:
(A)9 (B) 11 (C) 13.5 (D) 15 (E) 18.5
You can put this solution on YOUR website! Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a constant rate, the number of minutes before Jessica laps Sharon is:
---------------
On each lap Sharon gains 10 seconds on Jessi's time.
In 9 laps Sharon will have gained a full lap on Jessi.
---
9 laps will take Sharon 900 seconds
900 seconds = 900/60 = 15 minutes
-------------------------------------
Cheers,
Stan H.
===========================
(A)9 (B) 11 (C) 13.5 (D) 15 (E) 18.5