SOLUTION: 2x^2+y^2-12x-16y+10=0 how do i convert this to standard form of a conic section
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Question 281302
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2x^2+y^2-12x-16y+10=0
how do i convert this to standard form of a conic section
Answer by
richwmiller(17219)
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You can
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This an ellipse
2x^2-12x+y^2-16y+10=0
(x-3)^2+(y-8)^2=36