SOLUTION: A regulation double tennis court has an area of 2808 square feet. If it is 6 feet longer than twice its width, determine the size of the court.

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Question 281160: A regulation double tennis court has an area of 2808 square feet. If it is 6 feet longer than twice its width, determine the size of the court.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
AREA=LW
L=2W+6
2,808=(2W+6)W
2,808=2W^2+6W
2W^2+6W-2,808=0
2(W^2+3W-1,404)=0
2(W-36)(W+39)=0
W-3=0
W=36 ANS FOR THE WIDTH.
L=2*36+6=72+6=78 ANS. FOR THE LENGTH.
PROOF:
2,808=36*79
2,808=2,808