SOLUTION: please help me solve the followin function: f(x)= x^2-6x+2

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Question 280888: please help me solve the followin function:
f(x)= x^2-6x+2
Answer by nabla(475) About Me  (Show Source):
You can put this solution on YOUR website!
There really is nothing to "solve" here. This is simply a rule.
However, if you want the "roots" you will solve x^2-6x+2=0
We do this through an application of the quadratic formula.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-6x%2B2+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-6%29%5E2-4%2A1%2A2=28.

Discriminant d=28 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--6%2B-sqrt%28+28+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-6%29%2Bsqrt%28+28+%29%29%2F2%5C1+=+5.64575131106459
x%5B2%5D+=+%28-%28-6%29-sqrt%28+28+%29%29%2F2%5C1+=+0.354248688935409

Quadratic expression 1x%5E2%2B-6x%2B2 can be factored:
1x%5E2%2B-6x%2B2+=+1%28x-5.64575131106459%29%2A%28x-0.354248688935409%29
Again, the answer is: 5.64575131106459, 0.354248688935409. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-6%2Ax%2B2+%29