SOLUTION: Train A & B are traveling in the same direction on parallel track. Train A is traveling 80 miles per hour and train B is traveling 90 miles per hour. Train A passes station at 3:10

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Question 280838: Train A & B are traveling in the same direction on parallel track. Train A is traveling 80 miles per hour and train B is traveling 90 miles per hour. Train A passes station at 3:10 pm If train B passes same station at 3:22 pm what time will train B catch up to train A
Found 3 solutions by stanbon, Alan3354, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Train A & B are traveling in the same direction on parallel track.
Train A is traveling 80 miles per hour and train B is traveling 90 miles per hour.
Train A passes station at 3:10 pm If train B passes same station at 3:22 pm what time will train B catch up to train A?
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Train A DATA:
rate = 80 mph ; time = x hrs ; distance = rt = 80x miles
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Train B DATA:
rate = 90 mph ; time = (x-(12/60)) hrs ; distance = 90(x-(1/5)) miles
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Equation:
distance = distance
80x = 90x - 18
10x = 18
x = 1.8 hrs = 1 hr 48 minutes
===================================
Cheers,
Stan H.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Train A & B are traveling in the same direction on parallel track. Train A is traveling 80 miles per hour and train B is traveling 90 miles per hour. Train A passes station at 3:10 pm If train B passes same station at 3:22 pm what time will train B catch up to train A
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at 322, train A is 16 miles from the station (80 mph * 12/60)
Train B gains on train A at 10 mph (90 - 80)
16 miles at 10 mph --> 1.6 hours or 1 hr 36 minutes
322 + 136 = 4:58 PM

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I have a stopwatch.
I'll start it when the 2nd train, train B, passes the station
Train A passed the station 12 min ago at 3:10
How far did train A get in 12/60 hr? That is his headstart
80%2A%2812%2F60%29+=+16 mi
Now write equations for each train, with time = t for both,
since I'll stop the stopwatch when they meet
d%5BA%5D+=+80t
d%5BB%5D+=+90t
Also note that d%5BA%5D+=+d%5BB%5D+-+16
Substituting:
(1) d%5BB%5D+-+16+=+80t
(2)+d%5BB%5D+=+90t
Substituting again:
90t+-+16+=+80t
10t+=+16
t+=+1.6 hr
B will catch A in 1 hour 36 min, or at 3:22 + 1:36 = 4:58 PM
check:
d%5BA%5D+=+80%2A1.6
d%5BA%5D+=+128
d%5BB%5D+=+90%2A1.6
d%5BB%5D+=+144
144+-+128+=+16
16+=+16
OK