SOLUTION: the perimeter of a rectangle is 132 inches. The length exceeds the width by 46 inches. Find the length and width.
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-> SOLUTION: the perimeter of a rectangle is 132 inches. The length exceeds the width by 46 inches. Find the length and width.
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Question 280830: the perimeter of a rectangle is 132 inches. The length exceeds the width by 46 inches. Find the length and width. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! Perimeter of a rectangle = 2*length + 2*width.
l = length
w = width
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P = 132 :: given
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l = w+46 :: given
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Substituting into the perimeter equation...
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2l + 2w = 132
2(w+46) + 2w = 132
2w + 92 + 2w = 132
4w + 92 = 132
4w = 40
w = 10
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l = w+46 = 56
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Checking this answer...
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P = 2*56 + 2*10
P = 112 + 20
P = 132
Correct.
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Answer:
Length = 56
Width = 10
.
Done
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