SOLUTION: What are 4 consecutive positive integers whose sum equals 5 times the smallest integer?

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Question 280799: What are 4 consecutive positive integers whose sum equals 5 times the smallest integer?
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Four consecutive positive integers can be described as a, b, c, and d.
But it is better to define them in terms of one another.
a = x
b = x+1
c = x+2
d = x+3
.
We are told the sum is 5 times the smallest number.
.
x + (x+1) + (x+2) + (x+3) = 5x
.
collecting terms...
4x + 6 = 5x
6 = x
x = 6
.
So the possible consecutive positive integers are 6, 7, 8 and 9.
.
Checking the solution, is the sum = 5*6 = 30?
6+7+8+9 =30
Correct!
.
Answer:
The consecutive positive digits are 6, 7, 8 and 9.
.
Done