SOLUTION: how much water should be added to 30gallons of a solution that is 70% antifreeze in order to get a mixture that is 60% antifreeze? thank you

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Question 280773: how much water should be added to 30gallons of a solution that is 70% antifreeze in order to get a mixture that is 60% antifreeze? thank you
Found 2 solutions by Alan3354, Grinnell:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a problem that's similar.
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How many liters of a 40% acid solution must be added to 12 liters of a 20% solution to obtain a 25% solution?
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.4x + 12*.2 = (12+x)*.25
Solve for x
x is the amount added

Answer by Grinnell(63) About Me  (Show Source):
You can put this solution on YOUR website!
30(.70)=(30+x).60
x is the amount of water added, in gallons.
30 +x is the final amount of solution, in gallons.
Again we multiply by 100, removing the decimal.
2100=1800+60x
300=60x
5=x so 5 gallons should be added.