SOLUTION: find vertex of the parabola y=4x squared - 16x - 11

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Question 280601: find vertex of the parabola y=4x squared - 16x - 11
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
y=4x^2-16x-11
vertex
x=-b/2a
x=-(-16)/2*4
x=16/8=2
y=4*2^2-16*2-11
y=16-32-11
y=-16-11
y=-27
(2,-27)