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Question 280591: find the slope of the line passing through the points (7,0) and (0,10)
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! The slope of a line is defined as the rise/run, where
rise = change in y = y2 - y1
run = change in x = x2 - x1
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It is important to keep your definitions of the points staight too.
(x1, y1) = (7,0)
(x2, y2) = (0,10)
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rise = y2 - y1 = 10 -0 = 10
run = x2 - x1 = 0 -7 = -7
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slope = 10/-7 = -10/7
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The slope-intercept equation is y = mx+b
y = -10/7x + b
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We are given the point (0,10), so we know when x=0, y=10.
y = -10/7x + 10
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Looking at graph, we see it slopes down from the upper left to the lower right, which is what we expect with a negative slope.
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We can check by computing another point and seeing whether it is on the line or not.
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y = -10/7x + 10
x = 14
y = -10/7*14 + 10
y = -20 + 10
y = -10
So, is the point (14,-10) on the graph?
Yes, it appears to be.
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Reviewing the question, what answer is needed?
Just the slope...
The slope of the line is -10/7.
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Done.
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