SOLUTION: 28x^3-23x^2-57x-18/7x+3
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Question 280579
:
28x^3-23x^2-57x-18/7x+3
Answer by
richwmiller(17219)
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You can
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nice expression! what about it?
Do you mean
(28x^3-23x^2-57x-18)/(7x+3)
It reduces to
and then factors to
Which becomes