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Question 28054: 2x-4y=8
-3x+6y=5
Answer by bosun1(3)   (Show Source):
You can put this solution on YOUR website! 2x-4y=8
-3x+6y=5
SINCE 3X IS CARRYING A NEGATIVE SIGN
THEN SOLVE FOR X 1ST.
X3 2X-4Y=8
X2 -3X+6Y=5
MULTIPLY 3 BY THE 1ST ROLE AND MULTIPLY 2 BY THE SECOND ROLE.
GIVES YOU: 6X-12Y=24
-
-6X+12Y=10
GIVES YOU 12X=14
DIVIDE BOTH SIDE BY 12
12X/12=14/12
GIVES YOU X=7/6
PICK ONE OF THE EQUATION FRON THE QUETION BEING GIVEN AND SUBSTITUTE X WHICH IS 7/6
2X-4Y=8
2[7/6]-4Y=8
7/3-4Y=8
SUBTRACT 7/3 FROM BOTH SIDE
7/3-7/3-4Y=8-7/3
-4Y=17/3
DIVIDE BOTH SIDE BY -4
-4Y/-4=17/3 / -4
THEREFORE Y= - 17/12
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