SOLUTION: I got a couple that are really stumping me, can you show them with the steps? Factor out First: x3 – 26x2 + 48x Second:3x^2 – 2x – 8 Third: x2 – 5x – 14 Thanks You hav

Algebra ->  Rational-functions -> SOLUTION: I got a couple that are really stumping me, can you show them with the steps? Factor out First: x3 – 26x2 + 48x Second:3x^2 – 2x – 8 Third: x2 – 5x – 14 Thanks You hav      Log On


   

Question 28046: I got a couple that are really stumping me, can you show them with the steps?
Factor out
First: x3 – 26x2 + 48x
Second:3x^2 – 2x – 8
Third: x2 – 5x – 14
Thanks You have been a great help
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1st: common factor of "x"
Rewrite as x(x^2-26x+48)
Factor the quadratic as (x-2)(x-24)
Final answer x(x-2)(x-24)
2nd: ac = Product of 3 and -8 = -24
b=-2
Find two numbers whose product is ac and whose sum is b
Numbers are -6 and 4
Rewrite original problem as follows:
3x^2-6x+4x-8
Factor the 1st two terms and the last two terms separately to get:
3x(x-2)+4(x-2)
Factor again to get:
(x-2)(3x+4)
Cheers,
Stan H.