SOLUTION: Sky divers. Bob and Betty simultaneously jump from
two airplanes at different altitudes. Bob’s altitude
t seconds after leaving his plane is -16t^2 + 6600 feet.
Betty’s altitude
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-> SOLUTION: Sky divers. Bob and Betty simultaneously jump from
two airplanes at different altitudes. Bob’s altitude
t seconds after leaving his plane is -16t^2 + 6600 feet.
Betty’s altitude
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Question 280338: Sky divers. Bob and Betty simultaneously jump from
two airplanes at different altitudes. Bob’s altitude
t seconds after leaving his plane is -16t^2 + 6600 feet.
Betty’s altitude t seconds after leaving her plane is
-16t^2 + 7400 feet. Write a polynomial that represents the
difference between their altitudes t seconds after leaving
the planes. What is the difference between their altitudes
3 seconds after leaving the planes?
You can put this solution on YOUR website! Bob(t) = 6600 - 16t^2
Betty(t) = 7400 - 16t^2
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Betty(t) - Bob(t) = 800 feet
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For all values of t, the difference is 800 feet as long as they're in freefall, ignoring air resistance and other physical differences.
