SOLUTION: if the side of an equilateral triangle are given by (2a-b-3),(a-b+1) and (2a-2b-1),then the perimeter (in cms) of the triangle is
a. 6
b. 9
c. 12
d. 15
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-> SOLUTION: if the side of an equilateral triangle are given by (2a-b-3),(a-b+1) and (2a-2b-1),then the perimeter (in cms) of the triangle is
a. 6
b. 9
c. 12
d. 15
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Question 280314: if the side of an equilateral triangle are given by (2a-b-3),(a-b+1) and (2a-2b-1),then the perimeter (in cms) of the triangle is
a. 6
b. 9
c. 12
d. 15 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! if the side of an equilateral triangle are given by (2a-b-3),(a-b+1) and (2a-2b-1),then the perimeter (in cms) of the triangle is
a. 6
b. 9
c. 12
d. 15
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2a-b-3 = a-b+1 = 2a-2b-1
2a-3 = a+1
a = 4
--------
8-b-3 = 8-2b-1
b+3 = 2b+1
b = 2
------
Perimeter = 8-2-3 + 4-2+1 + 8-4-1 = 3 + 3 + 3
P = 9
