SOLUTION: The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle. (I tried to double the diagonal dimensions and multiply L*W, but I

Algebra ->  Rectangles -> SOLUTION: The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle. (I tried to double the diagonal dimensions and multiply L*W, but I       Log On


   

Question 28026: The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle.
(I tried to double the diagonal dimensions and multiply L*W, but I could not come up with the right answer)
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
The diagonal of a rectangle is 10 inches and the area is 45 square inches. Find the dimensions the rectangle.
(I tried to double the diagonal dimensions and multiply L*W, but I could not come up with the right answer)
area =LW=45..............OR...........L=45/W
DIAGONAL =SQUARE ROOT OF (L^2+W^2)=10...SQUARING BOTH SIDES ...
L^2+W^2=100
45^2/W^2+W^2=100
LET W^2=X
2025/X+X=100
2025+X^2=100X
X^2-100X+2025=0
USING THE QUADRATIC FORMULA
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=28.2O55
HENCE W =SQRT(X)=5.31
L=45/5.31=8.47