Question 280041: The number of accidents that occur at the intersection of Pine and Linden streets between 3 p.m. and 6 p.m. on Friday afternoon is 0, 1, 2, or 3, with probabilities of 0.84, 0.13, 0.02, and 0.01, respectively. Graph this probability distribution. What is the expected value for the random variable given the number of accidents?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The number of accidents that occur at the intersection of Pine and Linden streets between 3 p.m. and 6 p.m. on Friday afternoon is 0, 1, 2, or 3, with probabilities of 0.84, 0.13, 0.02, and 0.01, respectively. Graph this probability distribution. What is the expected value for the random variable given the number of accidents?
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Procedure:
Multiply each random number value by its corresponding probability.
Add the set of 4 products to get the expected value.
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E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
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Cheers,
Stan H.
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