SOLUTION: Solve by using quadratic formula {{{x^2 – 4x + 29 = 0}}}

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Question 279904: Solve by using quadratic formula x%5E2+%96+4x+%2B+29+=+0
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+-+4x+%2B+29+=+0
Compare that to

{{ax^2+bx+c=0}}}

a=1, b=-4, c=29 

Substitute that in

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 



x+=+%284+%2B-+sqrt%28+16+-+116%29%29%2F2

x+=+%284+%2B-+sqrt%28-100%29%29%2F2

x+=+%284+%2B-+i%2Asqrt%28100%29%29%2F2

x+=+%284+%2B-+10i%29%2F2

x+=+4%2F2+%2B-+10i%2F2

x+=+2+%2B-+5i

Edwin