Question 279804: (-3,0) 2y=x-1 don't inder stand how to do it show me how and the answere is in slope-intercept form. Found 2 solutions by JBarnum, solver91311:Answer by JBarnum(2146) (Show Source):
You can put this solution on YOUR website! first off that equation isnt in slope intercept form, second i dont know what u are asking how to do what theres no instructions, do u need to find more points on the same line? you have a point and the line that passes through it what is it u need help with?
(-3,0) 2y=x-1
(-3,0) are u trying to see if this point is on the line? this point is not on the line
please be more specific with your questions
JBarnum is right -- you have to tell us what you want. Put in the entire question. Having said that, I'm going to go out on a limb here and guess that you want the equation, in slope-intercept form, that is either parallel or perpendicular to the graph represented by and that passes through the point .
First step is to find the slope of the given line. The easiest way to do that is to solve the equation for in terms of everything else and then examine the coefficient on
Multiply both sides of the equation by :
The coefficient on is , so the slope of the given line is .
Now you need to determine the slope of the desired line. If you are looking for a line parallel to the given line, then parallel lines have identical slopes.
In other words:
That means the slope of the line you are trying to find is .
On the other hand if you want a line that is perpendicular to the given line then the slope of the desired line is the negative reciprocal of the slope of the given line, thus:
That would mean that the slope of the desired line is
Next you need to use the point-slope form of the equation of a line:
where are the coordinates of the given point and is the slope of the desired line. In this case, those values are: and either or
Just substitute the values:
or
Finally, do the algebra required to put your equation into slope-intercept form which is
