SOLUTION: Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?

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Question 279720: Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(pounds of salt in final solution)/(pounds of salt + water in final solution) = 10%
Let w = pounds of water to be added
given:
The pounds of salt in final solution = 30%2A.15+=+4.5 pounds
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4.5%2F%2830+%2B+w%29+=+.1
4.5+=+.1%2A%2830+%2B+w%29
4.5+=+3+%2B+.1w
.1w+=+1.5
w+=+15 pounds
If 1 pint = 1 pound, then 15 pints of water should be added