SOLUTION: A storeowner buys a quality of balls for $600. If they had each cost $0.25 less, shewould have had 10 more for the same money. How much did she pay for each ball?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A storeowner buys a quality of balls for $600. If they had each cost $0.25 less, shewould have had 10 more for the same money. How much did she pay for each ball?      Log On


   

Question 2794: A storeowner buys a quality of balls for $600. If they had each cost $0.25 less, shewould have had 10 more for the same money. How much did she pay for each ball?
Answer by sujatha.krishna(11) About Me  (Show Source):
You can put this solution on YOUR website!
Assume
x = number of balls
y = cost of each ball
x * y = 600
y = 600/x
If each ball costed 0.25$ less, then she would have 10 balls more for the same cost -
(x+10) * (y-0.25) = 600
This when further simplified comes to
xy + 10y - 0.25x - 2.5 = 600
600 + 10y - x/4 - 2.5 = 600
10y -x/4 = 2.5
Multiplying this whole equation by 4
40y - x = 10
40 (600/x) - x = 10
Multiplying the whole equation by x
24000 - x2 = 10x
x2+10x=24000
So x =150 and hence y = 600/150 = 4
So the store owner bought 150 balls for 4$ each