SOLUTION: How do I solve 7/x = 9/x - 1/11? 6/z+8 = 5/z-3? 4-s/7-s = 3/s-7?

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Question 279249: How do I solve
7/x = 9/x - 1/11?
6/z+8 = 5/z-3?

4-s/7-s = 3/s-7?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do I solve
7/x = 9/x - 1/11?
Multiply thru by 11x to get:
77 = 99 - x
x = 99-77
x = 22
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6/z+8 = 5/z-3?
Cross-multiply:
6(z-3) = 5(z+8)
6z-18 = 5z+40
z = 58
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4-s/7-s = 3/s-7?
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Modify the fraction on the left by multiplying numerator and denominator by -1.
{(s-4)/(s-7)]= 3/(s-7)
Multiply both sides by s-7 to get:
s-4 = 3
s = 7
But s cannot be seven because the denominator is s-7 and
that would be zero if s = 7.
Conclusion: No solution
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Cheers,
Stan H.