SOLUTION: Find the value(s) of {{{k}}} for which {{{k+5x+x^2}}} can be factored.

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Find the value(s) of {{{k}}} for which {{{k+5x+x^2}}} can be factored.       Log On


   



Question 278999: Find the value(s) of k for which k%2B5x%2Bx%5E2 can be factored.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Find the value(s) of k for which k%2B5x%2Bx%5E2 can be factored.
Write it in descending order:

x%5E2%2B5x%2Bk

Suppose it factors as

%28x%2Ba%29%28x%2Bb%29

Then we can choose a and b as any two integers which
add to 5.

We can choose a=1, b=4, or a=2, b=3 

With the first choice,

%28x%2Ba%29%28x%2Bb%29 becomes

%28x%2B1%29%28x%2B4%29

which when FOILed out becomes

x%5E2%2B5x%2B4, so if k=4 then k%2B5x%2Bx%5E2 can be factored

With the second choice,

%28x%2Ba%29%28x%2Bb%29 becomes

%28x%2B2%29%28x%2B3%29

which when FOILed out becomes

x%5E2%2B5x%2B6, so if k=6 then k%2B5x%2Bx%5E2 can be factored

So the answer is:  If k = 4 or 6, then k%2B5x%2Bx%5E2 can

be factored.  Otherwise it can't.

Edwin