SOLUTION: Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same time ans walks toward Fred's house on the same path at a rate of 2 mi/hr. How long will it be

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Question 278823: Fred begins walking toward John's house at 3 mi/hr. John leaves his house at the same time ans walks toward Fred's house on the same path at a rate of 2 mi/hr. How long will it be before they meet if the distance between the houses is 4 miles?
Found 2 solutions by Stitch, richwmiller:
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
X%2A%283mi%2Fhr%29+=+4mi+-+X%2A%282mi%2Fhr%29
Simplify
%283Xmi%2Fhr%29+=+4mi+-+%282Xmi%2Fhr%29
Add %282Xmi%2Fhr%29 to both sides
%285Xmi%2Fhr%29+=+4mi Divide both sides by 5mi/hr
X+=+%284%2F5%29h
We can convert this to minutes
1 hour = 60 min
%284%2F5%29+%2A+60+=+48min
They will meet each other 48 min after leaving their houses.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
3*x+2*x=4
5x=4
x=4/5
x=4/5 hour
4/5*60=48 minutes
They met after walking 48 minutes
3*4/5=12/5=2.4 miles Fred walked 2.4 miles
2*4/5=8/5=1.6 miles john walked 1.6 miles