SOLUTION: Women's weights are normally distributed with a mean given by 143 lb and a standard deviation given by 29 lb. Find the first decile, which separates the bottom 10% from the top 90%

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Question 278499: Women's weights are normally distributed with a mean given by 143 lb and a standard deviation given by 29 lb. Find the first decile, which separates the bottom 10% from the top 90%.
Answer by stanbon(75887) About Me  (Show Source):
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Women's weights are normally distributed with a mean given by 143 lb and a standard deviation given by 29 lb. Find the first decile, which separates the bottom 10% from the top 90%.
Find the z-value which has a left tail of 10%.
invNorm(10) = -1.2816
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Find the x-value associated with that z-value:
x = zs + u
z = -1.2816*29 + 143
z = 105.84
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Cheers,
Stan H.