SOLUTION: Hyperbolas again, i need to find the vertecies foci and slope then graph the equation: 4x^2-25y^2-8x^2-96 equals zero(0) please help me!

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Hyperbolas again, i need to find the vertecies foci and slope then graph the equation: 4x^2-25y^2-8x^2-96 equals zero(0) please help me!      Log On


   

Question 27827: Hyperbolas again,
i need to find the vertecies foci and slope then graph the equation: 4x^2-25y^2-8x^2-96 equals zero(0)
please help me!
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
%284x%5E2-8x%29-25y%5E2-96=0
4%28x%5E2-2x%29-25%28y%5E2%29-96%2B0 ---> complete the square
4%28x%5E2-2x%2B1-1%29-25%28y%5E2%29-96%2B0
4%28%28x-1%29%5E2-1%29-25%28y%5E2%29-96=0
4%28x-1%29%5E2-4-25%28y%5E2%29-96=0
4%28x-1%29%5E2-25%28y%5E2%29-100=0
4%28x-1%29%5E2-25%28y%5E2%29=100
%28x-1%29%5E2%2F25-y%5E2%2F4=1


Center at (1,0)
Foci (c)=4+25=29
c=sqrt%2829%29

Foci of hyperbola at c=sqrt%2829%2B1%2C0%29 and c=sqrt%28-29%29%2B1%2C0
a%5E2=25
a=5
Vertices
(5+1,0) and (-5+1,0)
Sorry I do not know about the slope and how to graph it here.

Paul.