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| Question 27808:  I need help using the substitution method so can you help me solve this problem:
 3x+5y=-3
 -3x+y=-15
 I also need help using the combination method so maybe with these too:
 1) 4x+5y=-2
 5x=5-10y
 2) 3y=16-2x
 5x+2y=14
 Last question is on graphing inequalities, i think:
 4x+3y (is less then or equal to) 13
 -3x+4y>9
 Answer by sdmmadam@yahoo.com(530)
      (Show Source): 
You can put this solution on YOUR website! I need help using the substitution method so can you help me solve this problem: 3x+5y=-3
 -3x+y=-15
 I also need help using the combination method so maybe with these too:
 1) 4x+5y=-2
 5x=5-10y
 2) 3y=16-2x
 5x+2y=14
 Last question is on graphing inequalities, i think:
 4x+3y (is less than or equal to) 13
 -3x+4y(is greater than or equal to) 9
 1)Substitution method:
 3x+5y=-3 ----(1)
 -3x+y=-15 ----(2)
 From (2), we have y = 3x-15 ----(*)
 (adding 3x to both the sides or transferring -3x from LHS to RHS, change side then change sign)
 Substituting for y in (1),
 3x + 5(3x-15) = -3
 3x +5X3x - 5X15 = -3
 3x+15x -75 =-3
 18x = -3+75
 18x = 72
 x = 72/18 = (18X4)/18 = 4
 Putting x= 4 in (*),
 y = 3x - 15
 = 3X4 - 15 = 12-15 = -3
 Answer: x=4 and y = -3
 Verification: We have used (2) for our finding the variables.So we use (1)for verification.
 Putting x=4 and y = -3 in (1)
 3x+5y=-3 ----(1)
 LHS = 3X4 +5X(-3) = 12-15 = -3 =RHS
 Therefore our  values are correct.
 I also need help using the combination method so maybe with these too:
 1) 4x+5y=-2
 5x=5-10y
 2) 3y=16-2x
 5x+2y=14
 Combination method:
 1) 4x+5y=-2
 5x=5-10y
 First of all see to it that both  the equations are in the  form Ax+By = C
 The given equations are
 4x+5y=-2  ----(1)X 2
 5x+10y= 5 ----(2) (bringing -10y from the  right  side to the left side)
 Observe that 5 and 10 are the coefficients of y respectively in the equations.
 And  their lcm is 10.
 Why take the lcm? It is for equalising  the coefficients of the variable  we want to eliminate.
 Since  5X2 = 10, multiply equation (1) through out  by 2
 8x+10y=-4  ----(3)
 5x+10y= 5  ----(2)
 (3) - (2)gives
 (8x-5x) + 0 = (-4-5) (you may do vertical subtraction and  get  the answer faster)
 3x = -9
 x = -9/3 = -3
 Putting x= -3 in (1),
 4x+5y=-2  ----(1)
 4X(-3) + 5y = -2
 -12+5y = -2
 5y = +12-2
 5y = 10
 y = 10/5 = 2
 Answer: x = -3 and y = 2
 Verification:Putting x = -3 and y = 2 in (2)
 5x+10y= 5  ----(2)
 LHS = 5x+10y
 = 5X(-3)+10X2
 =-15+20
 =+5 =RHS  which is correct
 2) 3y=16-2x
 5x+2y=14
 The given  equation are
 2x+3y = 16 ----(1)X 2
 5x+2y = 14 ----(2)X 3
 (lcm of the coefficients of y is 6)
 4x + 6y = 32 ----(3)
 15x + 6y = 42 ----(4)
 (3) - (4)implies
 (4x-15x)+ (6y - 6y) = 32 - 42
 -11x +0 = -10
 -11x = -10
 x = (-10)(-11) = 10/11
 x=10/11 in (1)gives
 2X(10/11) + 3y = 16
 20/11 + 3y = 16
 3y = 16-20/11
 3y = (16X11-20)/11
 3y = (176-20)/11
 3y = 156/11
 y = (3X52)/(3X11)
 y = 52/11
 Answer: x =10/11 and y = 52/11
 Verification: Putting x =10/11 and y = 52/11 in  5x+2y = 14 ----(2)
 LHS = 5x+2y
 =5x(10/11) + 2X(52/11)
 = 50/11 +104/11 =(50+104)/11 = 154/11 = (11X14)/11 = 14 =RHS which is correct
 PLEASE NOTE:
 The inequality problem has symbols like less than or equal to and greater than or equal and hence I have done the problem under a different application and I tried to  copy it using print screen,  copy, paste feature. It does not seem to work.Hence if you could give me your email address may be my attachment will work.
 
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