SOLUTION: 1. Solve for x. 3/10 = 5/x where / means a fraction bar. 2. Divide and simplify: The fraction (x^2-4)/(x) divided by the fraction (4x - 8) / (x) 3. Add and s

Algebra ->  Expressions-with-variables -> SOLUTION: 1. Solve for x. 3/10 = 5/x where / means a fraction bar. 2. Divide and simplify: The fraction (x^2-4)/(x) divided by the fraction (4x - 8) / (x) 3. Add and s      Log On


   

Question 277833: 1. Solve for x. 3/10 = 5/x where / means a fraction bar.

2. Divide and simplify: The fraction (x^2-4)/(x) divided by the fraction
(4x - 8) / (x)

3. Add and simplify: The fraction 4/(a^2 -1) + the fraction (1)/(2a + 2)
4. Using the LCD, solve: 3 + the fraction (1)/(x - 2) = the fraction
(2x - 3) / (x - 2)
Show use of the LCD.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
1. Solve for x. 3/10 = 5/x
cross multiply
3x=5*10
3x=50
x=50/3
x=16 2/3 ans

2. Divide and simplify: The fraction (x^2-4)/(x) divided (4x-8)/(x)
Invert the denominator & multiply.
(x^2-4)/x*x/(4x-8) cross multiply
(x^2-4)/4(x-2)
(x+2)(x-2)/(x-2) cancel out the (x-2 terms.
x+2 ans.

3. Add and simplify: The fraction 4/(a^2-1)+(1)/(2a+2)
Find the LCD (a^2-1)(2a+2)
[4(2a+2)+(a^2-1)]/(a^2-1)(2a+2)
[4*2(a+1)+(a+1)(a-1)]/(a+1)(a-1)*2(a+1)
[(8+1)(a+1)(a-1)]/3(a+1)(a-1)
[8(a+1)(a-1)]/3(a+1)(a-1) cancel out 3(a+1) & (a-1)
5(a+1) ans.
4. Using the LCD, solve: 3+(1)/(x-2)=(2x-3)/(x-2)
LCD=(x-2)
3(x-2)+1/(x-2)=(2x-3)/x-2)
[3x-6+1]/(x-2)=(2x-3)/(x-2) cancel out the denominators.
3x-5=2x-3
3x-2x=-3+5
x=2 ans.
Proof is not valid because (2-2)=0 & you cannot divide by 0.
Show use of the LCD.