SOLUTION: I need help on this new form of equation that we're learning in school that I still don't understand. It evidently has something to do with parabolas. Here's the problem: In fir

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need help on this new form of equation that we're learning in school that I still don't understand. It evidently has something to do with parabolas. Here's the problem: In fir      Log On


   



Question 277762: I need help on this new form of equation that we're learning in school that I still don't understand. It evidently has something to do with parabolas. Here's the problem:
In firefighting, a good water stream can be modeled by:
y=-0.003x^2 + 0.62x + 3
where x is the water's horizontal distance traveled (in feet) and y is its corresponding height (in feet). If a firefighter is aiming a good water stream at a building's window 25 feet above the ground, at what two distances can the firefighter stand from the building?
Please help me. I have no idea where to even start.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
25 will be y the height
so plug in 25 for y and find x
(x-161.165) (x-45.5022) = 0