SOLUTION: Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 160 miles in the same time that Dana travels 145 miles. If Chuck's rate of travel is 3 mph more than Dana's,
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Question 277732: Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 160 miles in the same time that Dana travels 145 miles. If Chuck's rate of travel is 3 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
160=(R+3)T
T=160/(R+3)
145=RT
T=145/R
SEEING AS THE TIMES ARE THE SAME:
160/(R+3)=145/R CROSS MULTIPLY.
160R=145(R+3)
160R=145R+435
160R-145R=435
15R=435
R=435/15
R=29 MPH FOR DANA'S RATE.
29+3=32 MPH FOR CHUCK'S RATE.
PROOF:
160/32=145/29
5=5
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