SOLUTION: if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second interger. find the third interger

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Question 277701: if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second interger. find the third interger
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) About Me  (Show Source):
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if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second interger. find the third interger
Let the numbers be x, x+2 and x+4

x+(x+4)+87=5(x+2)
2x+4+87=5x+10
2x-5x=-4-87+10
-3x=-81
x= 27
the other two numbers are 89 and 91


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 1st integer be F

Then the 2nd and 3rd integers are F + 2 and F + 4, respectively

Sum of 1st and 3rd integers = F + F + 4, or 2F + 4

Therefore, 2F + 4 = 5(F + 2) – 87

2F + 4 = 5F + 10 – 87

2F - 5F = - 4 + 10 – 87

-3F = - 81

F = %28-81%29%2F%28-3%29 = 27

Since the 1st integer, or F equals 27, then the 3rd integer is highlight_green%2831%29(F + 4) = 27 + 4